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256x^2-144=0
a = 256; b = 0; c = -144;
Δ = b2-4ac
Δ = 02-4·256·(-144)
Δ = 147456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{147456}=384$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-384}{2*256}=\frac{-384}{512} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+384}{2*256}=\frac{384}{512} =3/4 $
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